d \( \left(0.125+\frac{4}{8}\right)^{2} \times \frac{64}{125}-1 \)
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Solución
Respondido por UpStudy AI y revisado por un tutor profesional
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The Deep Dive
First, let's simplify the expression inside the parentheses: \( 0.125 + \frac{4}{8} \) can be calculated by converting \( 0.125 \) to a fraction, which is \( \frac{1}{8} \). Thus: \[ \frac{1}{8} + \frac{4}{8} = \frac{5}{8}. \] Now, we square \( \frac{5}{8} \): \[ \left(\frac{5}{8}\right)^{2} = \frac{25}{64}. \] Next, we multiply by \( \frac{64}{125} \): \[ \frac{25}{64} \times \frac{64}{125} = \frac{25 \times 64}{64 \times 125} = \frac{25}{125} = \frac{1}{5}. \] Finally, we subtract 1: \[ \frac{1}{5} - 1 = \frac{1}{5} - \frac{5}{5} = -\frac{4}{5}. \] So, the final answer is: \[ -\frac{4}{5}. \]
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