Simplig the ff: friconometric expressin \( \frac{\cos \left(360^{\circ}-x\right) \cdot \operatorname{Sin}\left(360^{\circ}-x\right) \cdot \operatorname{Cos}\left(90^{\circ}-x\right)}{\sin ^{2}\left(00^{\circ}-x\right) \cdot \operatorname{Sin}\left(180^{\circ}+x\right)} \)
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To simplify the expression \[ \frac{\cos(360^\circ - x) \cdot \sin(360^\circ - x) \cdot \cos(90^\circ - x)}{\sin^2(0^\circ - x) \cdot \sin(180^\circ + x)}, \] we can use some trigonometric identities. 1. **Using the periodic and even/odd properties:** - \(\cos(360^\circ - x) = \cos(x)\) - \(\sin(360^\circ - x) = -\sin(x)\) - \(\cos(90^\circ - x) = \sin(x)\) - \(\sin(0^\circ - x) = -\sin(x)\) - \(\sin(180^\circ + x) = -\sin(x)\) 2. **Substituting these into the expression:** \[ \frac{\cos(x) \cdot (-\sin(x)) \cdot \sin(x)}{(-\sin(x))^2 \cdot (-\sin(x))} \] This simplifies to: \[ \frac{-\cos(x) \cdot \sin^2(x)}{\sin^2(x) \cdot (-\sin(x))} = \frac{\cos(x)}{\sin(x)} = \cot(x) \] Thus, the simplified expression is: \[ \cot(x) \]
