\( f ^ { \prime } ( x ) = ( e ^ { - x ^ { 2 } } ) ^ { \prime } \)
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Extra Insights
To solve for \( f'(x) = (e^{-x^2})' \), we can apply the chain rule. The derivative of \( e^{-x^2} \) involves taking the derivative of the exponent, which is \(-x^2\). The derivative of \(-x^2\) is \(-2x\). So, by applying the chain rule: \[ f'(x) = e^{-x^2} \cdot (-2x) = -2x e^{-x^2} \] This gives us the first derivative of the function. When dealing with exponentials, it’s essential to recognize that the chain rule often plays a crucial role in simplifying derivatives. A common mistake is forgetting to multiply by the derivative of the exponent, which can lead to incorrect results, so keep an eye out for that!
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