\( \begin{array}{l}\text { An order of brown rice and quinoa weighs } 17 \text { pounds and costs } \$ 54 \text {. } \\ \text { Brown rice: } \$ 2.00 \text { per pound } \\ \text { Quinoa: } \$ 4.50 \text { per pound } \\ \text { How many pounds of brown rice and quinoa are in this order? }\end{array} \) One way to solve this system is to substitute the value of one variable into the other equation. To do this, we can use either variable, \( q \) or \( b \). So, we need to know either: \( q= \) some value, so that we can substitute that value for \( q \), or, \( b= \) some value, so that we can substitute that value for \( b \). Is either equation written as \( q \) equals some value or \( b \) equals some value yet?
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Mind Expander
To figure out how many pounds of brown rice and quinoa are in the order, let’s start by defining our variables. We can let \( b \) represent the pounds of brown rice and \( q \) represent the pounds of quinoa. The weight equation can be expressed as \( b + q = 17 \). The cost equation would be \( 2b + 4.5q = 54 \). Now, we can solve for one variable. If we rearrange the weight equation, we get \( q = 17 - b \). This means you can substitute \( 17 - b \) in place of \( q \) in the cost equation, leading to a single equation with one variable, \( b \). This substitution makes it easier to find \( b \) and then \( q \).
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