What is the sum of the polynomials? \( 1.3 t^{3}+t^{2}-42 t+8 \) \( 1.3 t^{3}+t^{2}-6 t+8 \) \( 1.9 t^{3}+8.4 t^{2}-42 t \) \( 1.9 t^{2}-42 t+8 \) DONE

To find the sum of the given polynomials, we'll add the corresponding coefficients of like terms (i.e., terms with the same power of \( t \)). Let's list the polynomials: 1. \( 1.3 t^{3} + t^{2} - 42 t + 8 \) 2. \( 1.3 t^{3} + t^{2} - 6 t + 8 \) 3. \( 1.9 t^{3} + 8.4 t^{2} - 42 t \) 4. \( 1.9 t^{2} - 42 t + 8 \) **Step 1: Add the \( t^{3} \) terms** \[ 1.3 t^{3} + 1.3 t^{3} + 1.9 t^{3} + 0 t^{3} = 4.5 t^{3} \] **Step 2: Add the \( t^{2} \) terms** \[ 1 t^{2} + 1 t^{2} + 8.4 t^{2} + 1.9 t^{2} = 12.3 t^{2} \] **Step 3: Add the \( t \) terms** \[ -42 t - 6 t - 42 t - 42 t = -132 t \] **Step 4: Add the constant terms** \[ 8 + 8 + 0 + 8 = 24 \] **Putting it all together:** \[ 4.5 t^{3} + 12.3 t^{2} - 132 t + 24 \] **Final Answer:** \[ 4.5\,t^{3} + 12.3\,t^{2} - 132\,t + 24 \]