Pregunta
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(i) \( \left(7 x^{3} \times 4 x^{3}\right)+\left(7 x^{3}+4 x^{3}\right) \) (j) \( 4 x^{3} \times 5 x^{3}+10 x^{2} \times \) 2. Simplify the following: (a) \( \frac{x^{12}}{x^{7}} \) (b) \( \frac{x^{7}}{x^{12}} \) (c) \( \frac{4^{9}}{4^{6}} \) (d) \( \frac{4^{6}}{4^{9}} \) (e) \( \frac{a^{6} b^{8} c}{a^{8} b^{6} c} \) (f) \( \frac{8 p^{4}}{4 p^{-4}} \) 3. Simplify the following: (a) \( \left(x^{3}\right)^{4} \) (b) \( \quad\left(x^{2}\right)^{5} \) (c) \( \quad\left(x^{2}\right)^{2} \)

Ask by Turnbull Hart. in South Africa
Feb 24,2025

Solución de inteligencia artificial de Upstudy

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1. (i) 28x⁶ + 11x³ (j) [Incomplete expression; please provide the missing factor.] 2. (a) x⁵ (b) 1/x⁵ (c) 64 (d) 1/64 (e) b²/a² (f) 2p⁸ 3. (a) x¹² (b) x¹⁰ (c) x⁴

Solución

Below are the step‐by‐step solutions for each part. (Note: In part (j) it seems that the expression is incomplete. Please check and let me know if there is a missing factor.) ────────────────────────────── 1. Simplify the following:   (i) (7x³ × 4x³) + (7x³ + 4x³) Step 1. Multiply 7x³ by 4x³:   7x³ × 4x³ = 28x^(3+3) = 28x⁶. Step 2. Add 7x³ and 4x³:   7x³ + 4x³ = 11x³. Thus, the simplified expression is:   28x⁶ + 11x³. ──────────────────────────────   (j) 4x³ × 5x³ + 10x² × … As written, the second term “10x² × ” is missing the factor to multiply by. Could you please confirm if there is an additional factor so that I can help simplify the full expression? ────────────────────────────── 2. Simplify the following:   (a) x¹² ÷ x⁷    Using the quotient rule (subtract the exponents):    x¹²/x⁷ = x^(12–7) = x⁵.   (b) x⁷ ÷ x¹²    x⁷/x¹² = x^(7–12) = x^(–5) = 1/x⁵.   (c) 4⁹ ÷ 4⁶    4⁹/4⁶ = 4^(9–6) = 4³ = 64.   (d) 4⁶ ÷ 4⁹    4⁶/4⁹ = 4^(6–9) = 4^(–3) = 1/4³ = 1/64.   (e) (a⁶b⁸c) ÷ (a⁸b⁶c)    Divide each factor:    – a⁶/a⁸ = a^(6–8) = a^(–2)    – b⁸/b⁶ = b^(8–6) = b²    – c/c = 1    Thus, the result is: a^(–2)·b² = b²/a².   (f) (8p⁴) ÷ (4p^(–4))    Divide the numerical coefficients and subtract the exponents on p:    8/4 = 2 and p⁴/p^(–4) = p^(4 – (–4)) = p^(8)    Thus, the simplified expression is: 2p⁸. ────────────────────────────── 3. Simplify the following:   (a) (x³)⁴    Using the power rule (multiply the exponents):    (x³)⁴ = x^(3×4) = x¹².   (b) (x²)⁵    (x²)⁵ = x^(2×5) = x¹⁰.   (c) (x²)²    (x²)² = x^(2×2) = x⁴. ────────────────────────────── Final Answers: 1. (i) 28x⁶ + 11x³   (j) [Incomplete expression; please clarify.] 2. (a) x⁵   (b) 1/x⁵   (c) 64   (d) 1/64   (e) b²/a²   (f) 2p⁸ 3. (a) x¹²   (b) x¹⁰   (c) x⁴ Let me know if you need any further clarification or if you can provide the missing part for 1(j)!

Respondido por UpStudy AI y revisado por un tutor profesional

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Bonus Knowledge

Sure! Let’s simplify these expressions and have some fun with it! For (i), we have: \[ (7x^3 \times 4x^3) + (7x^3 + 4x^3) = 28x^6 + 11x^3 \] It's all about combining like terms and enjoying those colorful coefficients! For (j): \[ 4x^3 \times 5x^3 + 10x^2 \quad = 20x^6 + 10x^2 \] Multiplying powers is like a party for exponents—they just want to dance together! As for the simplifications: (a) \[ \frac{x^{12}}{x^{7}} = x^{12-7} = x^{5} \] (b) \[ \frac{x^{7}}{x^{12}} = x^{7-12} = x^{-5} \] (c) \[ \frac{4^{9}}{4^{6}} = 4^{9-6} = 4^{3} \] (d) \[ \frac{4^{6}}{4^{9}} = 4^{6-9} = 4^{-3} \] (e) \[ \frac{a^{6} b^{8} c}{a^{8} b^{6} c} = a^{6-8} b^{8-6} = \frac{1}{a^{2} b^{2}} \] (f) \[ \frac{8 p^{4}}{4 p^{-4}} = 2p^{4-(-4)} = 2p^{8} \] Now, for the next set: 3. (a) \[ \left(x^{3}\right)^{4} = x^{3 \cdot 4} = x^{12} \] (b) \[ \left(x^{2}\right)^{5} = x^{2 \cdot 5} = x^{10} \] (c) \[ \left(x^{2}\right)^{2} = x^{2 \cdot 2} = x^{4} \] Math can feel like magic when you see those exponents come together! Remember, practicing these concepts can make you a real math wizard!

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