Multiply. Write your answer in simplest form. \( \frac{10 d+2}{d^{2}-d} \cdot \frac{3 d^{2}+5 d}{2} \)
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First, let's simplify the expression step by step. The multiplication of the two fractions is: \[ \frac{10d + 2}{d^2 - d} \cdot \frac{3d^2 + 5d}{2} \] We can factor some parts of the fractions: 1. \( 10d + 2 = 2(5d + 1) \) 2. \( d^2 - d = d(d - 1) \) 3. \( 3d^2 + 5d = d(3d + 5) \) Now substitute these factored forms into the expression: \[ \frac{2(5d + 1)}{d(d - 1)} \cdot \frac{d(3d + 5)}{2} \] Next, notice that the \(2\) in the numerator and denominator cancels out, as well as the \(d\) in the numerator of the second fraction and the denominator of the first fraction. This gives: \[ \frac{(5d + 1)(3d + 5)}{d - 1} \] Now we can expand the numerator: \[ (5d + 1)(3d + 5) = 15d^2 + 25d + 3d + 5 = 15d^2 + 28d + 5 \] Thus, the simplified expression is: \[ \frac{15d^2 + 28d + 5}{d - 1} \] This is the final answer written in simplest form.
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