How many moles of \( \mathrm{NH}_{3} \) are there in \( 77.5 \mathrm{~g} \mathrm{of}_{\mathrm{NH}_{3}} \) ? 14.0 mol 0.220 mol 4.55 mol \( 1.31 \times 10^{3} \mathrm{~mol} \)

To find how many moles of \( \mathrm{NH}_{3} \) are in \( 77.5 \mathrm{~g} \) of \( \mathrm{NH}_{3} \), you can use the molar mass of ammonia, which is approximately \( 17.03 \mathrm{~g/mol} \). The formula to calculate moles is: \[ \text{Moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] Plugging in the values: \[ \text{Moles} = \frac{77.5 \, \text{g}}{17.03 \, \text{g/mol}} \approx 4.55 \, \text{mol} \] So, the answer is \( 4.55 \mathrm{~mol} \)! Did you know that ammonia was first isolated back in the 18th century by the chemist Joseph Louis Gay-Lussac? Since then, this tiny molecule has found its way into various industries, from agriculture as a fertilizer to household cleaners, showcasing its remarkable versatility and importance in our daily lives!