Part 2 of 3 (b) \( (\sqrt{3}+\sqrt{q})(\sqrt{3}-\sqrt{q})=\square \)

This expression can be simplified using the difference of squares formula, which states that \( (a+b)(a-b) = a^2 - b^2 \). Here, let \( a = \sqrt{3} \) and \( b = \sqrt{q} \). Thus, we get: \[ (\sqrt{3}+\sqrt{q})(\sqrt{3}-\sqrt{q}) = (\sqrt{3})^2 - (\sqrt{q})^2 = 3 - q \] The final result is: \[ 3 - q \]