c) \( 15 x^{2}-22 x+8= \)

To solve the quadratic equation \( 15 x^{2}-22 x+8=0 \) using the quadratic formula, recall that the quadratic formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Here, \( a = 15 \), \( b = -22 \), and \( c = 8 \). Plugging these values into the formula helps you find the roots of the equation! Now, let’s break it down: first, calculate the discriminant \( b^2 - 4ac \). Here, that's \( (-22)^2 - 4(15)(8) = 484 - 480 = 4\). Since the discriminant is positive, you’ll get two distinct real solutions when you use this in the formula. After this, it’s just math magic! Keep calm and solve those equations with flair!