Lesson 17: Different Compounding Intervals Let's find out what happens when we repeatedly apply the same percent increase at different intervals of time. 17.1: Returns Over Three Years Earlier, you learned about a bank account that had an initial balance of \( \$ 1,000 \) and earned 1\% monthly interest. Each month, the interest was added to the account and no other deposits or withdrawals were made. To calculate the account balance in dollars after 3 years, Elena wrote: \( 1,000 \cdot(1.01)^{36} \) and Tyler wrote: \( 1,000 \cdot\left((1.01)^{12}\right)^{3} \). Discuss with a partner: 1. Why do Elena's expression and Tyler's expression both represent the account balance correctly? 2. Kiran said, "The account balance is about \( 1,000 \cdot(1.1268)^{3} \)." Do you agree? Why or why not?
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Bonus Knowledge
Elena's expression \( 1,000 \cdot(1.01)^{36} \) accurately calculates the account balance because it accounts for 36 months of compounded interest directly from the monthly interest rate of 1%. Tyler's expression, when simplified, shows that he understands the principle of compounding over intervals; he calculates the effective growth per year using \( (1.01)^{12} \) for monthly compounding, then raises this to the power of 3 for three years. Both methods arrive at the same final balance due to the properties of exponentiation and compounding. Kiran's statement simplifies the calculation incorrectly because he mistakenly combines the power of 1.1268 with 3 years without correctly representing the periodic compounding. While 1.1268 might represent the growth factor after a certain period, Kiran's approach overlooks the fact that interest should be compounded, not multiplied, in this context. Thus, Elena and Tyler’s methods provide a more accurate representation of the growth of the balance over time.
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