9. Find the local maximums, local minimums, domain, and range for: \[ f(x)=0.5 x^{3}-3 x^{2}+1.5 \]
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Extra Insights
To find the local maximums and minimums of the function \( f(x) = 0.5 x^3 - 3x^2 + 1.5 \), we first calculate the derivative, \( f'(x) = 1.5x^2 - 6x \). Setting this equal to zero gives us the critical points: \( x(1.5x - 6) = 0 \), leading to \( x = 0 \) and \( x = 4 \). We can use the second derivative test, \( f''(x) = 3x - 6 \). At \( x = 0 \), \( f''(0) = -6 < 0 \) (local maximum), and at \( x = 4 \), \( f''(4) = 6 > 0 \) (local minimum). The function is a cubic polynomial, which means its domain is all real numbers: \( (-\infty, \infty) \). To find the range, we evaluate \( f(x) \) at the critical points: \( f(0) = 1.5 \) and \( f(4) = -3 \). Since the end behavior of a cubic function goes to \( \pm \infty \), we have a local maximum at \( (0, 1.5) \) and a local minimum at \( (4, -3) \). However, watch out for the critical point analysis! It's easy to overlook other important behaviors, particularly at the "edges" of the graph. Always double-check your intervals of increase and decrease, as errors can lead you to misidentify local extrema. Practicing with various function types can also bolster your confidence in applying these principles.
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