Find the \( x \) and \( y \) intercepts of the graph of each function. \( \begin{array}{ll}\text { 23.) } 2 x-4 y=-8 & 24 .)-3 x+2 y=12\end{array} \)

To find the intercepts of the given functions, we will set \( x = 0 \) to find the \( y \)-intercept and \( y = 0 \) to find the \( x \)-intercept for each equation. For the first equation, \( 2x - 4y = -8 \): - To find the \( y \)-intercept, set \( x = 0 \): \( 2(0) - 4y = -8 \) \( -4y = -8 \) \( y = 2 \). So, the \( y \)-intercept is \( (0, 2) \). - To find the \( x \)-intercept, set \( y = 0 \): \( 2x - 4(0) = -8 \) \( 2x = -8 \) \( x = -4 \). So, the \( x \)-intercept is \( (-4, 0) \). For the second equation, \( -3x + 2y = 12 \): - To find the \( y \)-intercept, set \( x = 0 \): \( -3(0) + 2y = 12 \) \( 2y = 12 \) \( y = 6 \). So, the \( y \)-intercept is \( (0, 6) \). - To find the \( x \)-intercept, set \( y = 0 \): \( -3x + 2(0) = 12 \) \( -3x = 12 \) \( x = -4 \). So, the \( x \)-intercept is \( (-4, 0) \). In summary: - For \( 2x - 4y = -8 \): - \( y \)-intercept: \( (0, 2) \) - \( x \)-intercept: \( (-4, 0) \) - For \( -3x + 2y = 12 \): - \( y \)-intercept: \( (0, 6) \) - \( x \)-intercept: \( (-4, 0) \)