\begin{tabular}{l|l} Subtract. \\ \( \begin{array}{ll}8 \frac{4}{5}-7 \frac{1}{3} & 8 \frac{4}{5}-7 \frac{1}{3}=\square \\ \text { (Simplify your answer. Type a } \\ \text { whole number, fraction, or a } \\ \text { mixed number.) }\end{array} \) \\ \end{tabular}

To subtract the mixed numbers \(8 \frac{4}{5}\) and \(7 \frac{1}{3}\), first convert both mixed numbers to improper fractions. For \(8 \frac{4}{5}\): \(8 \times 5 + 4 = 40 + 4 = 44\) So, \(8 \frac{4}{5} = \frac{44}{5}\). For \(7 \frac{1}{3}\): \(7 \times 3 + 1 = 21 + 1 = 22\) So, \(7 \frac{1}{3} = \frac{22}{3}\). Next, find a common denominator to subtract the fractions. The least common multiple of 5 and 3 is 15. Convert \(\frac{44}{5}\) and \(\frac{22}{3}\) to have a denominator of 15: \[ \frac{44}{5} = \frac{44 \times 3}{5 \times 3} = \frac{132}{15} \] \[ \frac{22}{3} = \frac{22 \times 5}{3 \times 5} = \frac{110}{15} \] Now perform the subtraction: \[ \frac{132}{15} - \frac{110}{15} = \frac{132 - 110}{15} = \frac{22}{15} \] Finally, convert \(\frac{22}{15}\) back to a mixed number: \[ 22 \div 15 = 1\quad \text{with a remainder of } 7 \] Thus, \(\frac{22}{15} = 1 \frac{7}{15}\). So, the final answer is: \[ \boxed{1 \frac{7}{15}} \]