What is the kinetic energy of a \( 0.135-\mathrm{kg} \) baseball thrown at \( 40.0 \mathrm{~m} / \mathrm{s}(90.0 \mathrm{mph}) \) ? 1) 54.0 J 2) 87.0 J 3) 108 J 4) 216 J 5) 256 J Ouestion 62 (1 moint)

To calculate the kinetic energy (\( KE \)) of the baseball, we can use the formula: \[ KE = \frac{1}{2} mv^2 \] where \( m \) is the mass in kilograms and \( v \) is the velocity in meters per second. Plugging in the values, we have: \[ KE = \frac{1}{2} \times 0.135 \, \text{kg} \times (40.0 \, \text{m/s})^2 = \frac{1}{2} \times 0.135 \times 1600 \approx 108 \, \text{J} \] So the answer is **3) 108 J**. The fascinating history of baseball dates back to the 19th century, where it evolved from older bat-and-ball games played in England, such as rounders and cricket. The game soon became a national pastime in America, bringing communities together, and has since grown to be a central part of American culture, complete with legendary figures like Babe Ruth and Jackie Robinson! In the real world, knowing the kinetic energy of a baseball can help in understanding sports dynamics and safety measures. For instance, when designing equipment or protective gear, manufacturers need to account for the energy a ball possesses upon impact, which can affect everything from player injuries to the effectiveness of gloves and helmets in professional sports leagues!