ACTIVITY 25 A man was injured in an accident and receives an income from a disability grant of R48 000 in the \( 1^{1 \text { t }} \) year. The grant increases by a fixed amount each year. me ON 1. What is the annual increase, if over 20 years, he would have received R 1435000 in total from the grant? 2. His initial annual expenditure is R26 000 and increases at a rate of R4000 per year. 3. In which year will his expenses exceed his income?
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Bonus Knowledge
To find the annual increase in the disability grant, we can denote it as \( x \). Over 20 years, his income would be the sum of an arithmetic series starting at R48,000, increasing by \( x \) each year. The formula for the total income over 20 years is: \[ \text{Total Income} = \text{Number of years} \times \text{Average of first and last term} \] Calculating the last term in the sequence, we find: \[ \text{Last term} = 48000 + 19x \] So the total income equation becomes: \[ 20 \times \left(\frac{48000 + (48000 + 19x)}{2}\right) = 1435000 \] This simplifies to: \[ 20 \times (48000 + 9.5x) = 1435000 \] From this, you can solve for \( x \) (the annual increase) and reach the amount he needs incremented each year. Next, let’s think about when his expenses will exceed his income. His expenditures start at R26,000 and increase by R4,000 each year. We need to identify the year \( n \) when: \[ \text{Expenditures} = 26000 + 4000(n - 1) \] \[ \text{Income} = 48000 + (n - 1)x \] Setting these equal to find \( n \): \[ 26000 + 4000(n - 1) > 48000 + (n - 1)x \] This equation can be solved for \( n \) to see when expenses surpass the income. Plugging your calculated \( x \) into the equation will give you the specific year. Happy calculating!
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