\begin{tabular}{l} 3.13. $$ 25325 \div 13 $$ using long division \ 2. In a certain grade 8 class the ratio of boys to girls is $$ 3: 5 $$. If there are 30 girls how many \ ys are there in class. Show ALL your working. \ A Calculator is marked at $$ R $$ R 399,99 is sold at a discount of $$ 25 \% $$. Determine its selling \ wrice. \ \hline\end{tabular}

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UpStudy AI · Accepted Answer

### Problem 1: $$25325 \div 13$$ using long division

1. **Divide the first part of the number:**  
   - $$13$$ goes into $$25$$ once since $$1 \times 13 = 13$$.  
   - Subtract: $$25 - 13 = 12$$.

2. **Bring down the next digit ($$3$$):**  
   - The new number is $$123$$.  
   - $$13$$ goes into $$123$$ nine times because $$9 \times 13 = 117$$.  
   - Subtract: $$123 - 117 = 6$$.

3. **Bring down the next digit ($$2$$):**  
   - The new number is $$62$$.  
   - $$13$$ goes into $$62$$ four times since $$4 \times 13 = 52$$.  
   - Subtract: $$62 - 52 = 10$$.

4. **Bring down the last digit ($$5$$):**  
   - The new number is $$105$$.  
   - $$13$$ goes into $$105$$ eight times because $$8 \times 13 = 104$$.  
   - Subtract: $$105 - 104 = 1$$.

The quotient is $$1948$$ with a remainder of $$1$$. Thus,  
$$
25325 \div 13 = 1948\text{ R }1\,.
$$

---

### Problem 2: Ratio of Boys to Girls

Given the ratio of boys to girls is $$3:5$$ and there are $$30$$ girls:

1. **Express the numbers in terms of a common factor $$x$$:**  
   - Boys $$= 3x$$  
   - Girls $$= 5x$$

2. **Find $$x$$ using the number of girls:**  
   $$
   5x = 30 \quad \Rightarrow \quad x = \frac{30}{5} = 6
   $$

3. **Determine the number of boys:**  
   $$
   3x = 3 \times 6 = 18
   $$

4. **Determine the total number of students:**  
   $$
   \text{Total} = 3x + 5x = 8x = 8 \times 6 = 48
   $$

Thus, there are $$18$$ boys and $$48$$ students in total.

---

### Problem 3: Selling Price of the Calculator

The calculator is originally marked at $$ R399.99 $$ and is sold at a discount of $$25\%$$.

1. **Calculate the discount multiplier:**  
   A discount of $$25\%$$ means the calculator is sold at $$100\% - 25\% = 75\%$$ of the original price. In decimal form, this is $$0.75$$.

2. **Calculate the selling price:**  
   $$
   \text{Selling Price} = 399.99 \times 0.75 \,.
   $$
   
   Multiply:
   $$
   399.99 \times 0.75 \approx 299.9925
   $$
   
   Rounding to two decimal places, the selling price is approximately:
   $$
   R299.99
   $$

Thus, the selling price of the calculator is approximately $$ R299.99 $$.
- **Problem 1:** $$25325 \div 13 = 1948$$ with a remainder of $$1$$. - **Problem 2:** There are $$18$$ boys and $$48$$ students in total. - **Problem 3:** The selling price of the calculator is approximately $$ R299.99 $$.

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