Pregunta
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\( \int_{0}^{\frac{5}{6}} \frac{\mathrm{dx}}{36 \mathrm{x}^{2}+25} \) Click the icon to view the table of general integration

Ask by Sherman Chan. in the United States
Mar 13,2025

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The integral from 0 to \( \frac{5}{6} \) of \( \frac{1}{36x^{2}+25} \) dx equals \( \frac{\pi}{120} \).

Solución

Calculate or simplify the expression \( \int_{0}^{\frac{5}{6}} \frac{1}{36x^{2}+25}dx \). Evaluate the integral by following steps: - step0: Evaluate using substitution: \(\int_{0}^{\frac{5}{6}} \frac{1}{36x^{2}+25} dx\) - step1: Evaluate the integral: \(\int \frac{1}{36x^{2}+25} dx\) - step2: Transform the expression: \(\int \frac{1}{25\tan^{2}\left(t\right)+25}\times \frac{5}{6}\sec^{2}\left(t\right) dt\) - step3: Simplify the expression: \(\int \frac{\sec^{2}\left(t\right)}{30\tan^{2}\left(t\right)+30} dt\) - step4: Simplify the expression: \(\int \frac{1}{30} dt\) - step5: Evaluate the integral: \(\frac{1}{30}t\) - step6: Substitute back: \(\frac{1}{30}\arctan\left(\frac{6}{5}x\right)\) - step7: Return the limits: \(\left(\frac{1}{30}\arctan\left(\frac{6}{5}x\right)\right)\bigg |_{0}^{\frac{5}{6}}\) - step8: Calculate the value: \(\frac{\pi }{120}\) The integral of \( \frac{1}{36x^{2}+25} \) from 0 to \( \frac{5}{6} \) is \( \frac{\pi}{120} \).

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Extra Insights

To solve the integral \( \int_{0}^{\frac{5}{6}} \frac{\mathrm{dx}}{36 \mathrm{x}^{2}+25} \), we can make a substitution to match the form in tables of general integration. Notice that \( 36x^2 + 25 \) can be rewritten as \( 25(1 + \frac{36}{25}x^2) \). This transformation suggests the use of the formula for the inverse tangent function. After performing the integration and applying the limits of integration, the final result will be obtained through evaluation. This integral has interesting roots in the study of calculus and can easily be extended to more complex integrals. Evaluating it helps to reinforce the concept of understanding how different forms of functions can be tackled with proper techniques. Engaging with integrals like this can lead to insights about their geometrical interpretations, related to areas under curves, and their significance in physical applications such as projectile motion and electrical circuits.

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