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The solution to the system of inequalities \( y < 2x + 1 \) and \( y \leq -x - 4 \) is the region in the coordinate plane below both lines, including the line \( y = -x - 4 \) but not including the line \( y = 2x + 1 \). The intersection point is \( \left(-\frac{5}{3}, -\frac{7}{3}\right) \).
Solución
To analyze the system of inequalities given:
1. \( y < 2x + 1 \)
2. \( y \leq -x - 4 \)
We can graph these inequalities to find the solution region.
### Step 1: Graph the first inequality \( y < 2x + 1 \)
- The line \( y = 2x + 1 \) is a straight line with a slope of 2 and a y-intercept of 1.
- Since the inequality is strict (\(<\)), we will use a dashed line to indicate that points on the line are not included in the solution.
- The region below this line represents the solution to the inequality.
### Step 2: Graph the second inequality \( y \leq -x - 4 \)
- The line \( y = -x - 4 \) has a slope of -1 and a y-intercept of -4.
- Since the inequality is non-strict (\(\leq\)), we will use a solid line to indicate that points on the line are included in the solution.
- The region below this line represents the solution to the inequality.
### Step 3: Find the intersection of the two inequalities
To find the intersection of the two lines, we can set them equal to each other:
\[
2x + 1 = -x - 4
\]
Solving for \( x \):
\[
2x + x = -4 - 1
\]
\[
3x = -5
\]
\[
x = -\frac{5}{3}
\]
Now, substitute \( x = -\frac{5}{3} \) back into one of the equations to find \( y \):
Using \( y = 2x + 1 \):
\[
y = 2\left(-\frac{5}{3}\right) + 1 = -\frac{10}{3} + 1 = -\frac{10}{3} + \frac{3}{3} = -\frac{7}{3}
\]
So the intersection point is:
\[
\left(-\frac{5}{3}, -\frac{7}{3}\right)
\]
### Step 4: Determine the solution region
The solution region is where the shaded areas of both inequalities overlap.
- The area below the dashed line \( y = 2x + 1 \) and below the solid line \( y = -x - 4 \) is the solution to the system of inequalities.
### Conclusion
The solution to the system of inequalities \( y < 2x + 1 \) and \( y \leq -x - 4 \) is the region in the coordinate plane that is below both lines, including the line \( y = -x - 4 \) but not including the line \( y = 2x + 1 \). The intersection point \( \left(-\frac{5}{3}, -\frac{7}{3}\right) \) is also part of the boundary of the solution region.
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