\( \left.\begin{array}{l}1 \text { Graphically solve the following system of linear equations. } \\ \begin{array}{l}y=x-2 \\ x=-1\end{array} \\ (x, y)=(\square) \square\end{array}\right) \)

To graphically solve the system of linear equations given by: 1. \( y = x - 2 \) 2. \( x = -1 \) we will follow these steps: ### Step 1: Graph the first equation The first equation \( y = x - 2 \) is a linear equation with a slope of 1 and a y-intercept of -2. This means that the line crosses the y-axis at the point (0, -2) and rises one unit up for every one unit it moves to the right. ### Step 2: Graph the second equation The second equation \( x = -1 \) is a vertical line that crosses the x-axis at -1. This line will extend infinitely in the y-direction. ### Step 3: Find the intersection point To find the solution to the system of equations, we need to determine where these two lines intersect. 1. From the second equation, we know that \( x = -1 \). 2. Substitute \( x = -1 \) into the first equation to find \( y \): \[ y = -1 - 2 = -3 \] ### Step 4: Write the solution The intersection point, which is the solution to the system of equations, is: \[ (x, y) = (-1, -3) \] Thus, the solution to the system of equations is: \[ (x, y) = (-1, -3) \]