Re-write the quadratic function below in Standard Form

To convert a quadratic function into standard form, you generally want to re-write it as \(y = a(x - h)^2 + k\), where \((h,k)\) is the vertex of the parabola. This typically involves completing the square. For example, if you start with \(y = 2x^2 + 8x + 5\), you first factor out the coefficient of \(x^2\) from the \(x\) terms: 1. \(y = 2(x^2 + 4x) + 5\) 2. Next, complete the square: Take half of the coefficient of \(x\) (which is 4), square it (which gives 4), and adjust inside the parentheses: 3. \(y = 2(x^2 + 4x + 4 - 4) + 5\) 4. This simplifies to: \(y = 2((x + 2)^2 - 4) + 5\) 5. Finally, distribute and simplify: \(y = 2(x + 2)^2 - 8 + 5\) leading to \(y = 2(x + 2)^2 - 3\). So the standard form would be \(y = 2(x + 2)^2 - 3\)! Is there a specific quadratic function you'd like help with?