GATMEA FOMTC \[ \begin{array}{ll} \text { KEY: } & \\ L=5 \mathrm{~m} & L L=7.5 \mathrm{~m} \\ W=5 \mathrm{~m} & H=500 \mathrm{~mm} \end{array} \] 13.1. Calculate the perimeter of the garden bed above. 1.3.2. Determine the area [in square melers) of the side labeled \( K \). \[ \text { You may use the formula: Area }=\text { Length } \times \text { Width } \] 1.3.3. The volume of soil that will be used to fill the fic...er bed to capacity is \( 95 \mathrm{m3} \). Calc area of the area occupied by the soll in the garden bed. Use the formula: Area of the base \( = \) Volume + Height

Let's solve the problem step by step. ### Step 1: Calculate the perimeter of the garden bed. The garden bed is rectangular, and the perimeter \( P \) can be calculated using the formula: \[ P = 2(L + W) \] where \( L \) is the length and \( W \) is the width. From the given data: - \( L = 5 \, \text{m} \) - \( W = 5 \, \text{m} \) Now, substituting the values into the formula: \[ P = 2(5 + 5) = 2(10) = 20 \, \text{m} \] ### Step 2: Determine the area of the side labeled \( K \). The area \( A \) can be calculated using the formula: \[ A = L \times W \] From the given data: - \( L = 5 \, \text{m} \) - \( W = 5 \, \text{m} \) Now, substituting the values into the formula: \[ A = 5 \times 5 = 25 \, \text{m}^2 \] ### Step 3: Calculate the area of the base occupied by the soil in the garden bed. We are given the volume of soil \( V = 95 \, \text{m}^3 \) and the height \( H = 500 \, \text{mm} = 0.5 \, \text{m} \) (since 1 m = 1000 mm). The area of the base \( A_b \) can be calculated using the formula: \[ A_b = \frac{V}{H} \] Now substituting the values: \[ A_b = \frac{95}{0.5} = 190 \, \text{m}^2 \] ### Summary of Results: 1. The perimeter of the garden bed is \( 20 \, \text{m} \). 2. The area of the side labeled \( K \) is \( 25 \, \text{m}^2 \). 3. The area of the base occupied by the soil in the garden bed is \( 190 \, \text{m}^2 \).