Add as indicated, and simplify if possible. \[ \frac{3}{y+5}+\frac{1}{2 y+1}=\square \]

To combine the fractions, we first need to find a common denominator, which will be \((y + 5)(2y + 1)\). Now, we rewrite each fraction with this common denominator: \[ \frac{3}{y+5} = \frac{3(2y+1)}{(y+5)(2y+1)} = \frac{6y + 3}{(y+5)(2y+1)} \] \[ \frac{1}{2y+1} = \frac{1(y+5)}{(2y+1)(y+5)} = \frac{y + 5}{(2y + 1)(y + 5)} \] Now we combine the two fractions: \[ \frac{6y + 3}{(y+5)(2y+1)} + \frac{y + 5}{(y+5)(2y+1)} = \frac{(6y + 3) + (y + 5)}{(y+5)(2y+1)} \] Simplifying the numerator: \[ 6y + 3 + y + 5 = 7y + 8 \] So, the combined fraction is: \[ \frac{7y + 8}{(y+5)(2y+1)} \] Thus, the final result is: \[ \frac{7y + 8}{(y+5)(2y+1)} = \square \]