Suppose that events \( E \) and \( F \) are independent. In addition, possible \( P(E)=0.45 \) and \( P(F)=0.2 \). What is \( P(E \) and \( F) \) ? \( P(E \) and \( F)=\square \) (Simplify your answer. Do not round.)

When two events \( E \) and \( F \) are independent, the probability of both events occurring, denoted \( P(E \text{ and } F) \), is given by the product of their individual probabilities. Thus, you can use the formula: \[ P(E \text{ and } F) = P(E) \times P(F) \] Plugging in the given values: \[ P(E \text{ and } F) = 0.45 \times 0.2 = 0.09 \] So, \[ P(E \text{ and } F) = 0.09 \]