\( \leftarrow \begin{array}{l}\text { Factor. } \\ 6 a^{2}+11 a-35\end{array} \)

To factor the quadratic 6a² + 11a − 35, follow these steps: 1. Multiply the coefficient of a² by the constant term: 6 × (−35) = −210. 2. Find two numbers that multiply to −210 and add to the middle coefficient, 11. The numbers 21 and −10 work since 21 × (−10) = −210 and 21 + (−10) = 11. 3. Rewrite the middle term using these numbers:   6a² + 21a − 10a − 35. 4. Group the terms:   (6a² + 21a) + (−10a − 35). 5. Factor each group:   3a(2a + 7) − 5(2a + 7). 6. Notice that (2a + 7) is common, so factor it out to get:   (2a + 7)(3a − 5). Thus, the factored form of 6a² + 11a − 35 is (2a + 7)(3a − 5).