(c) The original function $$ y=A(r) $$ converted an input, the circle's radius, to an output, the circle's area. What are the inputs and outputs of the inverse function? Input: REASOLput: 8. The domain and range of a one-to-one function, $$ y=f(x) $$, are given below in set-builder notation. Giv the domain and range of this function's inverse also in set-builder notation. $$ y=f(x) $$ Domain: $$ \{x \mid-3 \leq x-2\} $$

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(c) The original function $$ y=A(r) $$ converted an input, the circle's radius, to an output, the circle's area. What are the inputs and outputs of the inverse function? Input: REASOLput: 8. The domain and range of a one-to-one function, $$ y=f(x) $$, are given below in set-builder notation. Giv the domain and range of this function's inverse also in set-builder notation. $$ y=f(x) $$ Domain: $$ \{x \mid-3 \leq x<5\} $$ Range: $$ \{y \mid y>-2\} $$

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Part (c): The original function A takes a circle’s radius as its input and returns its area as the output. The inverse function reverses this process; it takes a circle’s area as its input and returns the corresponding circle’s radius as its output. ––––––––––––––– Part 8: The function f has Domain: { x ∣ –3 ≤ x < 5 } and Range: { y ∣ y > –2 }. For the inverse function, the domain and range are swapped. That is, Domain of f⁻¹: { x ∣ x > –2 } and Range of f⁻¹: { y ∣ –3 ≤ y < 5 }. Part (c): - **Input of the inverse function**: Circle's area - **Output of the inverse function**: Circle's radius Part 8: - **Domain of the inverse function**: $$ \{ x \mid x > -2 \} $$ - **Range of the inverse function**: $$ \{ y \mid -3 \leq y < 5 \} $$

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