EXERCISE (a) Simplify the followiag \( \begin{array}{lll}\text { (1) } \frac{2 x}{3}+\frac{1}{6} & \text { (2) } \frac{7}{6 x}-\frac{2}{9 y}+\frac{1}{3 x^{2}} & \text { (3) } \frac{3}{x}+\frac{2}{x^{2}} \\ \text { (4) } 1+2-\frac{2 a-1}{2} & \text { (5) } \frac{5}{6 x y}-\frac{x+2}{2 x} & \text { (6) } \frac{5}{2 x}-\frac{x+1}{x-2} \\ \text { (7) } \frac{2}{x}+\frac{5}{x+1} & \text { (8) } \frac{x+2}{x^{2}+2}-\frac{6}{x+2} & \text { (9) } \frac{x-3}{x+3}-\frac{x+3}{x-3} \\ \text { (10) } \frac{4}{(2 x+1)^{2}}-\frac{x+1}{2 x+1} & \text { (11) } \frac{2}{2 x}+\frac{7 x+1}{4 x^{2} y}-\frac{5 x y}{4}+1 \\ \text { (12) } \frac{x-3}{3}-\frac{x-2}{2}+\frac{x+1}{6} & \text { (13) } x-\frac{2 x}{3 x-2}\end{array} \)
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The Deep Dive
Let's have some fun simplifying those expressions step by step! For the first one, \(\frac{2x}{3} + \frac{1}{6}\), the least common denominator (LCD) is 6. Rewriting the first term gives us \(\frac{4x}{6} + \frac{1}{6} = \frac{4x + 1}{6}\). For the second expression, \(\frac{7}{6x} - \frac{2}{9y} + \frac{1}{3x^2}\), the LCD is \(18xy\). Rewriting each portion gives us \(\frac{21y}{18xy} - \frac{4x}{18xy} + \frac{6}{18xy}\), leading to \(\frac{21y - 4x + 6}{18xy}\). Keep this spirit of fun while diving through each expression; you'll be a pro in no time! If you need any specifics on the others, feel free to ask!
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