Given: \( f(x)=2 \tan x \quad \) and \( g(x)=\frac{1}{2} \tan x \quad, \quad x \in\left[0^{\circ} ; 360^{\circ}\right] \) 3.1 Sketch the graphs of \( f \) and \( g \) on the same set of axes. 3.2 If there is a point with coordinates \( \left(45^{\circ} ; a\right) \), in the graphs of \( f, g \) and \( y=\tan x \), Write down the value of \( a \) in the graphs of \( f, g \) and \( y=\tan x \). 3.3 The graphs are in the form \( y=a \tan x \) : Compare and comment on the values of \( a \) in the graphs of \( f . g \) and \( y=\tan x \).
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To sketch the graphs of \( f(x) = 2 \tan x \) and \( g(x) = \frac{1}{2} \tan x \), start by plotting the basic \( y = \tan x \) curve which has vertical asymptotes at \( 90^\circ \) and \( 270^\circ \) within the given range. The graph of \( f(x) \) will have the same asymptotes but with a steep slope, doubling the amplitude of the tangent function, whereas \( g(x) \) will be more relaxed, having half the steepness. Now, let's find the value of \( a \) at \( x = 45^\circ \). For the standard tangent function, \( \tan(45^\circ) = 1 \). Hence, using the definitions: - For \( f(45^\circ) = 2 \tan(45^\circ) = 2 \times 1 = 2 \), so \( a = 2 \). - For \( g(45^\circ) = \frac{1}{2} \tan(45^\circ) = \frac{1}{2} \times 1 = \frac{1}{2} \), so \( a = \frac{1}{2} \). - For \( y = \tan(45^\circ) = 1 \), \( a = 1 \). When comparing \( a \) values in \( f, g, \) and \( y = \tan x \): - For \( f \), \( a = 2 \) indicates it stretches the graph vertically, making it rise faster than \( \tan x \). - For \( g \), \( a = \frac{1}{2} \) signifies a compression, making it rise slower. - The original \( y = \tan x \) has \( a = 1 \), the standard slope. This fascinating interplay showcases how changing \( a \) affects the steepness and behavior of the graph!
