Question 2 The phone company A Fee and Fee has a monthly cellular plan where a customer pays a flat month and then a certain amount of money fier minute used on the phone. If a customer uses 190 minutes monthly cost will be \( \$ 83 \). If the customer uses 750 minutes, the monthly cost will be \( \$ 251 \). A) Find an equation in the form \( y=m x+b \), where \( x \) is the number of monthly minutes used and total monthly of the A Fee and Fee plan. Answer: \( y= \)

Given: - The monthly cost for using 190 minutes is $83. - The monthly cost for using 750 minutes is $251. Let's denote: - \( x \) as the number of monthly minutes used. - \( y \) as the total monthly cost of the A Fee and Fee plan. We can set up two equations based on the given information: 1. For 190 minutes: \( 83 = 190m + b \) 2. For 750 minutes: \( 251 = 750m + b \) We need to solve these two equations to find the values of \( m \) and \( b \) in the equation \( y = mx + b \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}83=190m+b\\251=750m+b\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}b=83-190m\\251=750m+b\end{array}\right.\) - step2: Substitute the value of \(b:\) \(251=750m+83-190m\) - step3: Subtract the terms: \(251=560m+83\) - step4: Swap the sides: \(560m+83=251\) - step5: Move the constant to the right side: \(560m=251-83\) - step6: Subtract the numbers: \(560m=168\) - step7: Divide both sides: \(\frac{560m}{560}=\frac{168}{560}\) - step8: Divide the numbers: \(m=\frac{3}{10}\) - step9: Substitute the value of \(m:\) \(b=83-190\times \frac{3}{10}\) - step10: Simplify: \(b=26\) - step11: Calculate: \(\left\{ \begin{array}{l}b=26\\m=\frac{3}{10}\end{array}\right.\) - step12: Check the solution: \(\left\{ \begin{array}{l}b=26\\m=\frac{3}{10}\end{array}\right.\) - step13: Rewrite: \(\left(b,m\right) = \left(26,\frac{3}{10}\right)\) The solution to the system of equations is: - \( b = 26 \) - \( m = 0.3 \) Therefore, the equation in the form \( y = mx + b \) is: \[ y = 0.3x + 26 \]