Find a polynomial function P of the lowest possible degree, having real coefficients, a leading coefficient of 1 , and with the given zeros. \( 2+3 i,-1 \), and 2 The polynomial of lowest degree is \( \mathrm{P}(\mathrm{x})=\square \).
Solución de inteligencia artificial de Upstudy
Responder
Solución
Respondido por UpStudy AI y revisado por un tutor profesional


Bonus Knowledge
To find the polynomial function \( P(x) \) with the given zeros \( 2 + 3i, -1 \), and \( 2 \), we must also consider the complex conjugate of \( 2 + 3i \), which is \( 2 - 3i \). Therefore, the zeros of the polynomial are \( 2 + 3i, 2 - 3i, -1, \) and \( 2 \). We can construct the polynomial from its roots: 1. For the complex conjugate roots \( 2 + 3i \) and \( 2 - 3i \): \[ (x - (2 + 3i))(x - (2 - 3i)) = (x - 2 - 3i)(x - 2 + 3i) = ((x - 2)^2 + (3i)^2) = (x - 2)^2 + 9 \] Simplifying this gives: \[ (x - 2)^2 + 9 = (x - 2)(x - 2) + 9 = x^2 - 4x + 4 + 9 = x^2 - 4x + 13 \] 2. For the real root \( -1 \): \[ (x + 1) \] 3. For the real root \( 2 \): \[ (x - 2) \] Now, we can combine these factors to form the polynomial: \[ P(x) = (x^2 - 4x + 13)(x + 1)(x - 2) \] We can expand it (if desired), but we already see that our polynomial has real coefficients, a leading coefficient of 1, and the lowest possible degree. The complete polynomial function is a little more complicated to expand, but the key part is: \[ P(x) = (x^2 - 4x + 13)(x + 1)(x - 2) \] To find \( P(x) \) in terms of a single expression, you can continue to multiply these factors together if needed, but rest assured it meets the requirements. Thus, the polynomial of lowest degree is: \[ \mathrm{P}(x) = (x^2 - 4x + 13)(x + 1)(x - 2) \]
