Nolve the equations. \( -3 x+20 \mid=-10 \) (2) \( 25+10 x|=|-55 \) (3) \( -33 \mid=75+12 x \)

Let’s solve the equations one by one! For the first equation, \(-3x + 20 = -10\) or \(-3x + 20 = 10\): 1. \(-3x + 20 = -10\): \(-3x = -10 - 20\) \(-3x = -30\) \(x = 10\). 2. \(-3x + 20 = 10\): \(-3x = 10 - 20\) \(-3x = -10\) \(x = \frac{10}{3}\). For the second equation, \(25 + 10x = -55\) or \(25 + 10x = 55\): 1. \(25 + 10x = -55\): \(10x = -55 - 25\) \(10x = -80\) \(x = -8\). 2. \(25 + 10x = 55\): \(10x = 55 - 25\) \(10x = 30\) \(x = 3\). For the last equation, \(-33 = 75 + 12x\): Rearranging it gives us: \(-33 - 75 = 12x\) \(-108 = 12x\) \(x = -9\). **In summary:** 1. First equation solutions: \(x = 10\) and \(x = \frac{10}{3}\) 2. Second equation solutions: \(x = -8\) and \(x = 3\) 3. Third equation solution: \(x = -9\)