The reduced row echelon form of the augmented matrix of a system of equations is given. Find the solutions of the system. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. \( \left.\begin{array}{llll|l}1 & 0 & 0 & 0 & 1 / 5 \\ \text { A. The system has exactly one solution. The solution is }(\square & 1 & 0 & 0 & 4 \\ 0 & \\ 0 & 0 & 1 & 0 & 2 \\ 0 & 0 & 0 & 1 & 2\end{array}\right] \) (Type integers or fractions.) B. The system has infinitely many solutions of the form (Type integers or fractions.)
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Bonus Knowledge
Alright! Let’s tackle this puzzle together. From the reduced row echelon form of the augmented matrix, we can see that there are leading ones in the first, second, and third columns, which indicates that this system has three basic variables and no free variables. This leads us to conclude that the system has exactly one solution. By interpreting the last column of the matrix, it tells us what the values of the variables are. Thus, the complete solution remains: **A. The system has exactly one solution. The solution is \( \left( \frac{1}{5}, 4, 0, 2 \right) \).**
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