As the air rises, it will continue to cool at the WAR of 3.4 degrees F per \( 1,000 \mathrm{ft} \). What will the temperature within the cloud be above Shreveport, LA at \( 11,000 \mathrm{ft} \) ? 10.4 degrees F 41 degrees F 14.6 degrees F

To find the temperature within the cloud above Shreveport, LA at \( 11,000 \mathrm{ft} \), you start with the base temperature at the ground level. If the temperature at ground level is, for example, 55 degrees F, you subtract the temperature drop due to the rising air. Now, for every \( 1,000 \mathrm{ft} \), the air cools by 3.4 degrees F. At \( 11,000 \mathrm{ft} \), the total cooling will be: \[ 3.4 \, \text{degrees F} \times 11 = 37.4 \, \text{degrees F} \] Then, subtract this cooling from the ground temperature: \[ 55 \, \text{degrees F} - 37.4 \, \text{degrees F} = 17.6 \, \text{degrees F} \] (assuming ground temp 55 degrees F; adjust accordingly based on actual ground temp) Based on the \( 11,000 \mathrm{ft} \) cooling effect, the answer is **none of the ones provided** match that, but you can see how it works! If we started at 55 degrees F, then after cooling, our best estimate would be around that temperature, hinting at how turbulent clouds can feel chilly once you ascend! Clouds usually hang around anywhere from 14.6 degrees F to 41 degrees F depending on the initial temperature you started from, so it helps to keep an actual local temperature in mind!