An equation and two ordered pairs are given. Show that each pair is a solution to the equation. Then use the graph of the two points to determine another solution. \( y=x-1 ;(0,-1) \) and \( (1,0) \) Is \( (0,-1) \) a solution of \( y=x-1 \) ? Yes

**Step 1. Verify \((0,-1)\) is a solution for \( y = x - 1 \)** Substitute \( x = 0 \) and \( y = -1 \) into the equation: \[ -1 = 0 - 1 \] Since both sides are equal, \((0,-1)\) is a solution. **Step 2. Verify \((1,0)\) is a solution for \( y = x - 1 \)** Substitute \( x = 1 \) and \( y = 0 \) into the equation: \[ 0 = 1 - 1 \] Again, both sides are equal, so \((1,0)\) is a solution. **Step 3. Determine another solution using the graph** The graph of \( y = x - 1 \) is a line with slope \(1\). Given the two points, we can move one unit to the right (increase \(x\) by 1) and one unit up (increase \(y\) by 1). For example, starting from \((1,0)\): - Increase \(x\) by 1: \( x = 1 + 1 = 2 \) - Increase \(y\) by 1: \( y = 0 + 1 = 1 \) Thus, another solution is \((2,1)\). Verifying this solution: \[ 1 = 2 - 1 \] Since the equality holds, \((2,1)\) is indeed another solution.