mediate Algebra L64 Noor Question Part 1 of 3 Completed: 19 of 20 My score: 15 Solve the linear inequality. Write the solution using set-builder notation and interval notation. Graph the solution set \[ 3[7-2(x+3)] \leq-3 x+9 \] The solution using set-builder notation is \( \{x \mid \) \( \square \)

Solve the equation \( 3[7-2(x+3)] \leq-3 x+9 \). Solve the inequality by following steps: - step0: Solve for \(x\): \(3\left(7-2\left(x+3\right)\right)\leq -3x+9\) - step1: Subtract the terms: \(3\left(1-2x\right)\leq -3x+9\) - step2: Expand the expression: \(3-6x\leq -3x+9\) - step3: Move the expression to the left side: \(-6x+3x\leq 9-3\) - step4: Add and subtract: \(-3x\leq 9-3\) - step5: Add and subtract: \(-3x\leq 6\) - step6: Change the signs: \(3x\geq -6\) - step7: Divide both sides: \(\frac{3x}{3}\geq \frac{-6}{3}\) - step8: Divide the numbers: \(x\geq -2\) The solution to the linear inequality \(3[7-2(x+3)] \leq -3x+9\) is \(x \geq -2\). Now, let's express the solution using set-builder notation and interval notation. Set-builder notation: \( \{x \mid x \geq -2 \}\) Interval notation: \([-2, \infty)\) Therefore, the solution set is \([-2, \infty)\).