Write the standard form of the equation and the general form of the equation of the circle of radius \( r \) and center ( \( h, k \) ). Graph the circle. \( r=\sqrt{3} ;(h, k)=(4,-2) \) The equation for the circle in standard form is \( \square \). (Simplify your answer.)
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Bonus Knowledge
The equation for the circle in standard form is \( (x - 4)^2 + (y + 2)^2 = 3 \). To convert this into general form, we expand it: 1. Expanding \( (x - 4)^2 \) gives \( x^2 - 8x + 16 \). 2. Expanding \( (y + 2)^2 \) gives \( y^2 + 4y + 4 \). 3. Now, combining these, we have: \( x^2 - 8x + 16 + y^2 + 4y + 4 - 3 = 0 \) Which simplifies to: \( x^2 + y^2 - 8x + 4y + 17 = 0 \). In terms of graphing, you can visualize this circle centered at (4, -2) with a radius \( \sqrt{3} \), which means it stretches about 1.73 units away from the center in all directions!
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