Q51 Determine the value of each unknown. a \( 2 x+1=7 \) b \( 2 x+4=14 \) c \( 3 x+5=11 \) d \( 5 x+1=36 \) e \( 2 x-1=5 \) f \( 2 x-3=7 \) \( 9 \quad 4 x-4=24 \) h \( 3 x-5=16 \) i \( 6 x-1=47 \) j \( 7 x-3=53 \) k \( 8 x+5=29 \) 1 \( 9 x-4=41 \)

To solve for each unknown, we'll isolate \(x\) in each equation. a) \(2x + 1 = 7\) Subtract 1 from both sides: \(2x = 6\) Now, divide by 2: \(x = 3\) b) \(2x + 4 = 14\) Subtract 4 from both sides: \(2x = 10\) Divide by 2: \(x = 5\) c) \(3x + 5 = 11\) Subtract 5 from both sides: \(3x = 6\) Divide by 3: \(x = 2\) d) \(5x + 1 = 36\) Subtract 1 from both sides: \(5x = 35\) Divide by 5: \(x = 7\) e) \(2x - 1 = 5\) Add 1 to both sides: \(2x = 6\) Divide by 2: \(x = 3\) f) \(2x - 3 = 7\) Add 3 to both sides: \(2x = 10\) Divide by 2: \(x = 5\) g) \(4x - 4 = 24\) Add 4 to both sides: \(4x = 28\) Divide by 4: \(x = 7\) h) \(3x - 5 = 16\) Add 5 to both sides: \(3x = 21\) Divide by 3: \(x = 7\) i) \(6x - 1 = 47\) Add 1 to both sides: \(6x = 48\) Divide by 6: \(x = 8\) j) \(7x - 3 = 53\) Add 3 to both sides: \(7x = 56\) Divide by 7: \(x = 8\) k) \(8x + 5 = 29\) Subtract 5 from both sides: \(8x = 24\) Divide by 8: \(x = 3\) l) \(9x - 4 = 41\) Add 4 to both sides: \(9x = 45\) Divide by 9: \(x = 5\) Here are the values of the unknowns: - a) \(x = 3\) - b) \(x = 5\) - c) \(x = 2\) - d) \(x = 7\) - e) \(x = 3\) - f) \(x = 5\) - g) \(x = 7\) - h) \(x = 7\) - i) \(x = 8\) - j) \(x = 8\) - k) \(x = 3\) - l) \(x = 5\)