10. \( \lim _{x \rightarrow 0} \frac{\sin 7 x}{x} \) 11. \( \lim _{x \rightarrow 0} \frac{\tan 3 x}{\sin 2 x} \)
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The limit \( \lim_{x \rightarrow 0} \frac{\sin 7 x}{x} \) can be evaluated using the fundamental limit \( \lim_{u \rightarrow 0} \frac{\sin u}{u} = 1 \). Here you can make the substitution \( u = 7x \), leading to \( \frac{\sin(7x)}{x} = 7 \frac{\sin(7x)}{7x} \), which gives you \( 7 \cdot 1 = 7 \) as the final answer. For the second limit \( \lim_{x \rightarrow 0} \frac{\tan 3 x}{\sin 2 x} \), you can again use the small-angle approximations. As \( x \) approaches 0, both \( \tan(3x) \) and \( \sin(2x) \) approximate their angles. Therefore, the limit becomes \( \frac{\tan(3x)}{\sin(2x)} ≈ \frac{3x}{2x} = \frac{3}{2} \), yielding a final answer of \( \frac{3}{2} \).
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