a. A point-slope form of the equation for the line shown is \( y-1=-\frac{3}{10}(x-5) \). (Type an equation.) b. The \( y \)-intercept of the line is about 2.5 . (Round to the nearest tenth as needed.) c. The line crosses the \( \square \) halfway between the given points so the \( y \)-intercept is halfway between the \( \square \) of the point on the left, the right, and that of the point on Type integers or decimals.)

**a. Equation in point‐slope form** We are given a point on the line and the slope. Using the point–slope form \[ y-y_1=m(x-x_1) \] with \((x_1,y_1)=(5,1)\) and \(m=-\frac{3}{10}\), the equation is \[ y-1=-\frac{3}{10}(x-5). \] **b. Finding the \(y\)-intercept** To find the \(y\)-intercept, substitute \(x=0\) into the equation: \[ y-1=-\frac{3}{10}(0-5). \] Simplify the right‐side: \[ 0-5=-5,\quad -\frac{3}{10}\times(-5)=\frac{15}{10}=1.5. \] Then, \[ y-1=1.5 \quad\Longrightarrow\quad y=1+1.5=2.5. \] Thus, the \(y\)-intercept is about \(2.5\). **c. Finding the halfway value on the square** The problem states that the line crosses a grid square halfway between two given points, so the \(y\)-intercept is halfway between the \(y\)-values at the left and right sides of that square. In this case, the two \(y\)-values are \[ 1\quad\text{and}\quad 4. \] To find the midpoint of these \(y\)-values, compute the average: \[ \frac{1+4}{2}=\frac{5}{2}=2.5. \] Thus, the \(y\)-intercept is the average of the two \(y\)-values, \(2.5\), which confirms our answer. Final answers: a. \(y-1=-\frac{3}{10}(x-5)\) b. \(2.5\) c. \(2.5\) is halfway between \(1\) and \(4\).