Pregunta
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\( 9 k \geq 0 \) or \( k+5<-3 \)

Ask by Powers Hart. in the United States
Feb 20,2025

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\( k \geq 0 \) or \( k < -8 \).

Solución

Solve the equation by following steps: - step0: Solve for \(k\): \(9k=0\) - step1: Rewrite the expression: \(k=0\) Solve the equation \( k+5=-3 \). Solve the equation by following steps: - step0: Solve for \(k\): \(k+5=-3\) - step1: Move the constant to the right side: \(k=-3-5\) - step2: Subtract the numbers: \(k=-8\) Let's solve the inequalities step by step. 1. **First Inequality: \( 9k \geq 0 \)** To solve this inequality, we can set it equal to zero to find the boundary point: \[ 9k = 0 \implies k = 0 \] Since \( 9k \) is greater than or equal to zero, \( k \) can be any value greater than or equal to 0. Thus, the solution for this inequality is: \[ k \geq 0 \] 2. **Second Inequality: \( k + 5 < -3 \)** We can solve this by isolating \( k \): \[ k + 5 = -3 \implies k = -3 - 5 \implies k = -8 \] Since this is a strict inequality, the solution is: \[ k < -8 \] ### Final Solution The overall solution to the compound inequality \( 9k \geq 0 \) or \( k + 5 < -3 \) is: - \( k \geq 0 \) or \( k < -8 \) This means \( k \) can take any value in the ranges \( (-\infty, -8) \) or \( [0, \infty) \).

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The Deep Dive

To solve this compound inequality, let's take each part one at a time! The first part, \( 9k \geq 0 \), tells us that \( k \) can be zero or positive, meaning \( k \geq 0 \). Now, for the second part, \( k + 5 < -3 \), we can isolate \( k \) by subtracting 5 from both sides, giving us \( k < -8 \). So, combining these results, the solution is that \( k \) is either any non-negative number (from the first inequality) or any number less than -8 (from the second inequality). You could represent this in interval notation as \( (-\infty, -8) \cup [0, \infty) \).

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