onsider the function \( f(x)=\left(\frac{1}{3}\right)^{x} \). . Is \( f \) an increasing or decreasing function? Give a reason for your anower .2 Determine \( f^{-1}(x) \) in the form \( y=- \) .3 Write down the equation of the asymptote of \( f(x)-5 \). .4 Describe the transformation from \( f \) in \( g \) if \( g(x)=\log _{3} x \).
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Bonus Knowledge
The function \( f(x) = \left(\frac{1}{3}\right)^{x} \) is a decreasing function because as \( x \) increases, the base \( \frac{1}{3} \) raised to a higher power results in smaller values. Essentially, we're flipping the numbers: smaller bases with exponents yield lesser outputs, making the function slide downwards as you move along the x-axis. To find the inverse \( f^{-1}(x) \), start by setting \( y = f(x) = \left(\frac{1}{3}\right)^{x} \), then solve for \( x \): we can rewrite it as \( \log_{\frac{1}{3}}(y) = x \). Changing the base gives us \( x = -\log_{3}(y) \), hence \( f^{-1}(x) = -\log_{3}(x) \). The equation of the asymptote of \( f(x) - 5 \) is \( y = -5 \). This comes from observing that \( f(x) \) approaches 0 as \( x \) heads towards infinity, meaning subtracting 5 shifts this horizontal line downwards without affecting the direction of approach. The transformation from \( f(x) \) to \( g(x) = \log_{3} x \) can be understood as a reflection and a shift. The logarithmic function represents the inverse of exponential decay, indicating that as the output of \( f(x) \) decreases, the input \( g(x) \) effectively captures that behavior by shifting our perspective from y-values into x-values, making it a fascinating flip from one function type to another!
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