A car service charges customers a flat fee per ride (which is higher during rush hour traffic) plus charges for each minute and each mile. Suppose that, in a certain metropolitan area during rush hour, the flat fee is \( \$ 5 \), the cost per minute is \( \$ 0.30 \), and the cost per mile is \( \$ 1.20 \). Let \( x \) be the number of minutes and \( y \) the number of miles. At the end of a ride, the driver said that the passenger owed \( \$ 11.30 \) and remarked that the number of minutes was three times the number of miles. Find the number of minutes and the number of miles for this trip. \( 3+U .3 u x+1.20 y=11.30 \) (Do not include the \( \$ \) symbol in your answer. Do not simplify. Use integers or decimals for any numbers in the equation.) Complete the equation that represents the relationship between the number of minutes and number of miles. \( \square=0 \) (Do not simplify. Use integers or decimals for any numbers in the equation.)

To solve this problem, we begin by translating the information into equations based on the cost structure provided. Let \( x \) represent the number of minutes, and \( y \) represent the number of miles. From the driver's remarks, "the number of minutes was three times the number of miles," we can express that relationship as: \( x = 3y \). Now, substituting this into the cost equation, we know that the total cost for the ride is the flat fee plus the cost per minute and per mile. This leads us to the equation: \( 5 + 0.30x + 1.20y = 11.30 \). Subtract the flat fee of 5 from both sides: \( 0.30x + 1.20y = 6.30 \). Now we can substitute \( x = 3y \) into this equation: \( 0.30(3y) + 1.20y = 6.30 \). This simplifies to: \( 0.90y + 1.20y = 6.30 \), which further simplifies to: \( 2.10y = 6.30 \). Dividing both sides by 2.10 gives: \( y = 3 \). Using \( y = 3 \) in the relationship \( x = 3y \) yields: \( x = 3(3) = 9 \). Hence, the number of minutes is \( 9 \) and the number of miles is \( 3 \). The complete cost equation reflecting the relationship is thus: \( 3 - y = 0 \).