4. Factorize: Factorize: (i) $$ x^{2}-12 x- $$ Factorize: Find HCF (i) $$ (a+b)^{2}, a^{2}-b^{2} $$

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Let's tackle each part of your request step by step.

### Part 1: Factorize $$ x^{2} - 12x $$

To factor the expression $$ x^{2} - 12x $$, we can look for common factors:

1. Identify the common factor: Both terms have $$ x $$ as a common factor.
2. Factor out $$ x $$:

$$
x^{2} - 12x = x(x - 12)
$$

So, the factorization of $$ x^{2} - 12x $$ is:

$$
x(x - 12)
$$

### Part 2: Find HCF of $$ (a+b)^{2} $$ and $$ a^{2}-b^{2} $$

To find the highest common factor (HCF) of the two expressions $$ (a+b)^{2} $$ and $$ a^{2}-b^{2} $$, we can first factor each expression.

1. **Factor $$ (a+b)^{2} $$**:
   - This is already in its factored form.

2. **Factor $$ a^{2} - b^{2} $$**:
   - This is a difference of squares, which can be factored as:
   $$
   a^{2} - b^{2} = (a - b)(a + b)
   $$

Now we have:
- $$ (a+b)^{2} $$
- $$ (a-b)(a+b) $$

### Finding the HCF:
The common factor in both expressions is $$ (a+b) $$.

Thus, the HCF of $$ (a+b)^{2} $$ and $$ a^{2}-b^{2} $$ is:

$$
(a+b)
$$

### Summary:
1. The factorization of $$ x^{2} - 12x $$ is $$ x(x - 12) $$.
2. The HCF of $$ (a+b)^{2} $$ and $$ a^{2}-b^{2} $$ is $$ (a+b) $$.
1. Factorization of $$ x^{2} - 12x $$: $$ x(x - 12) $$. 2. HCF of $$ (a+b)^{2} $$ and $$ a^{2}-b^{2} $$: $$ (a+b) $$.

4. Factorize: Factorize: (i) \( x^{2}-12 x- \) Factorize: Find HCF (i) \( (a+b)^{2}, a^{2}-b^{2} \)

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