Solve \( 6 x(x+2)=-42 \) by completing the square \( x=\square \)
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Extra Insights
To solve the equation \( 6x(x + 2) = -42 \), let's first rearrange it into a standard form. We can simplify it by dividing both sides by 6: \[ x(x+2) = -7 \] Now, expand the left side: \[ x^2 + 2x + 7 = 0 \] To solve this by completing the square, we move the constant to the other side: \[ x^2 + 2x = -7 \] Next, we'll complete the square on the left side. Take half of the coefficient of \(x\) (which is 2), square it (getting 1), and add it to both sides: \[ x^2 + 2x + 1 = -7 + 1 \] This simplifies to: \[ (x + 1)^2 = -6 \] Now, take the square root of both sides: \[ x + 1 = \pm i\sqrt{6} \] Isolating \(x\): \[ x = -1 \pm i\sqrt{6} \] So the solutions are: \[ x = -1 + i\sqrt{6} \quad \text{and} \quad x = -1 - i\sqrt{6} \]
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