Pregunta
? Exercise 3.7.5 Find the horizontal and vertical intercepts of \( f(x)=\frac{(x+1)(x-4)}{(x-3)(x+7)} \). Horizontal intercepts: \( (x, y)= \) (list all, separated by commas) Vertical intercept: \( (x, y)=\square \)
Ask by Haynes Murphy. in the United States
Feb 24,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
Horizontal intercepts: (-1, 0), (4, 0)
Vertical intercept: (0, 4/21)
Solución
To find the intercepts of the function f(x) = ((x + 1)(x - 4)) / ((x - 3)(x + 7)):
1. Horizontal intercepts (x-intercepts):
• Set the numerator equal to 0:
(x + 1)(x - 4) = 0.
Solutions: x + 1 = 0 ⟹ x = -1 , x - 4 = 0 ⟹ x = 4.
• Both x = -1 and x = 4 are acceptable provided they do not make the denominator zero (check: -1 ≠ 3, -1 ≠ -7; 4 ≠ 3, 4 ≠ -7).
• Therefore, the horizontal intercepts are: (-1, 0) and (4, 0).
2. Vertical intercept (y-intercept):
• Set x = 0:
f(0) = ((0 + 1)(0 - 4)) / ((0 - 3)(0 + 7)) = (1 * (-4)) / ((-3) * 7) = (-4) / (-21) = 4/21.
• Thus, the vertical intercept is: (0, 4/21).
Final Answers:
Horizontal intercepts: (-1, 0), (4, 0) Vertical intercept: (0, 4/21)
Respondido por UpStudy AI y revisado por un tutor profesional
Como
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The Deep Dive
To find the horizontal intercepts of the function \( f(x)=\frac{(x+1)(x-4)}{(x-3)(x+7)} \), we set \( f(x) = 0 \). The function is equal to zero when the numerator is zero, so we solve \( (x+1)(x-4) = 0 \). This gives us the intercepts at \( x = -1 \) and \( x = 4 \). Therefore, the horizontal intercepts are \( (-1, 0), (4, 0) \). For the vertical intercept, we evaluate \( f(0) \): \( f(0) = \frac{(0+1)(0-4)}{(0-3)(0+7)} = \frac{(1)(-4)}{(-3)(7)} = \frac{-4}{-21} = \frac{4}{21} \). Thus, the vertical intercept is \( (0, \frac{4}{21}) \).
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