Compute and simplify the difference quotient for each function given. a) \( f(x)=2 x-3 \) b) \( g(x)=x^{2}+3 \) c) \( h(x)=\frac{2}{x} \)
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To compute and simplify the difference quotient for each function, we use the formula \( \frac{f(x + h) - f(x)}{h} \) where \( h \) is a small increment approaching zero. Let's go through each function step by step. **a)** For \( f(x) = 2x - 3 \): 1. Calculate \( f(x + h) = 2(x + h) - 3 = 2x + 2h - 3 \). 2. Now, compute \( f(x + h) - f(x) = (2x + 2h - 3) - (2x - 3) = 2h \). 3. So, the difference quotient becomes \( \frac{f(x + h) - f(x)}{h} = \frac{2h}{h} = 2 \). Thus, the simplified difference quotient for \( f(x) \) is **2**. --- **b)** For \( g(x) = x^2 + 3 \): 1. Calculate \( g(x + h) = (x + h)^2 + 3 = x^2 + 2xh + h^2 + 3 \). 2. Now, compute \( g(x + h) - g(x) = (x^2 + 2xh + h^2 + 3) - (x^2 + 3) = 2xh + h^2 \). 3. So, the difference quotient becomes \( \frac{g(x + h) - g(x)}{h} = \frac{2xh + h^2}{h} = 2x + h \). Thus, the simplified difference quotient for \( g(x) \) is **2x + h**. --- **c)** For \( h(x) = \frac{2}{x} \): 1. Calculate \( h(x + h) = \frac{2}{x + h} \). 2. Now, compute \( h(x + h) - h(x) = \frac{2}{x + h} - \frac{2}{x} \). 3. This can be combined: \[ \frac{2}{x + h} - \frac{2}{x} = \frac{2x - 2(x + h)}{x(x + h)} = \frac{-2h}{x(x + h)}. \] 4. So, the difference quotient becomes \( \frac{h(x + h) - h(x)}{h} = \frac{-2h}{h \cdot x(x + h)} = \frac{-2}{x(x + h)} \). Thus, the simplified difference quotient for \( h(x) \) is **\(-\frac{2}{x(x + h)}\)**.
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