The function \( h(x)=\frac{1}{x+7} \) can be expressed in the form \( f(g(x)) \), where \( g(x)=(x+7) \), and \( f(x) \) is defined as: \( f(x)=\square \)

To express the function \( h(x) = \frac{1}{x+7} \) in the form \( f(g(x)) \), we can first identify \( g(x) = x + 7 \). Now, we need to define \( f(x) \) in such a way that when we substitute \( g(x) \) into \( f \), we get \( h(x) \). Since \( g(x) = x + 7 \), we want \( f(g(x)) = h(x) = \frac{1}{g(x)} \). Therefore, if we let \( f(x) = \frac{1}{x} \), substituting \( g(x) \) gives us: \[ f(g(x)) = f(x + 7) = \frac{1}{x + 7} = h(x). \] So, we can define \( f(x) = \frac{1}{x} \).