Pregunta
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9 Levi determined that \( y=2 \) is NOT a linear function because it does not take the form \( y=m x+b \). a. Explain why Levi's reasoning is incorrect. b. How else could Levi have determined whether the graph was linear or nonlinear?

Ask by Hilton Hamilton. in the United States
Mar 11,2025

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Levi's reasoning is incorrect because \( y=2 \) is actually a linear function. It can be written as \( y = 0x + 2 \), which fits the form \( y = mx + b \). Alternatively, Levi could have recognized that the graph of \( y=2 \) is a horizontal straight line, confirming it's linear.

Solución

1. **Part a** Levi's reasoning is incorrect because the function \( y=2 \) can be expressed in the form \( y = mx + b \) by writing it as \[ y = 0x + 2. \] Here, \( m=0 \) and \( b=2 \). Even though the slope is zero, the function is still linear. 2. **Part b** Another way Levi could have determined that the graph is linear is by noticing that the graph of \( y=2 \) is a horizontal line. Since every horizontal line is straight and has a constant rate of change (zero slope), it meets the definition of a linear graph.

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Mind Expander

Levi's reasoning is incorrect because the equation \( y=2 \) represents a horizontal line where the output \( y \) is always 2, regardless of the input \( x \). This still fits within the broader definition of a linear function, as it can be expressed in the slope-intercept form with \( m=0 \) and \( b=2 \). Linear functions can indeed take any constant form, making \( y=2 \) linear! To determine if a graph is linear or nonlinear, Levi could check how the values change when inputting different values for \( x \). If the change in \( y \) remains constant (which it does in this case since \( y \) is always 2), the graph is linear. Alternatively, plotting multiple points could visually show whether the relationship forms a straight line or curves.

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