For \( f(x)=x^{3} \) and \( g(x)=\sqrt[3]{x} \), find \( (f \circ g)(x) \) and \( (g \circ f)(x) \). Then determine whether \( (f \circ g)(x)=(g \circ f)(x) \). What is \( (f \circ g)(x) \) ? \( (f \circ g)(x)=\square \)
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To find \( (f \circ g)(x) \), we need to evaluate \( f(g(x)) \). First, we know: - \( g(x) = \sqrt[3]{x} \) - \( f(x) = x^3 \) Now we substitute \( g(x) \) into \( f(x) \): \[ (f \circ g)(x) = f(g(x)) = f(\sqrt[3]{x}) = (\sqrt[3]{x})^3 = x \] So, \( (f \circ g)(x) = x \). Now let's calculate \( (g \circ f)(x) \): We compute \( g(f(x)) \): \[ (g \circ f)(x) = g(f(x)) = g(x^3) = \sqrt[3]{x^3} = x \] Thus, \( (g \circ f)(x) = x \) as well. Finally, we can compare the two results: \[ (f \circ g)(x) = x \quad \text{and} \quad (g \circ f)(x) = x \] Therefore, \( (f \circ g)(x) = (g \circ f)(x) \).
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