Pregunta
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exact decimal. \( \int\left(8-7 x^{4}+\frac{3}{x^{16}}+18 \sqrt{x^{7}}\right) d x \)

Ask by Mullins Matthews. in South Africa
Mar 17,2025

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The integral of \(8 - 7x^{4} + \frac{3}{x^{16}} + 18\sqrt{x^{7}}\) with respect to \(x\) is \(8x - \frac{7x^{5}}{5} - \frac{1}{5x^{15}} + 4x^{4}\sqrt{x} + C\), where \(C\) is a constant.

Solución

Calculate the integral \( \int(8-7x^{4}+\frac{3}{x^{16}}+18\sqrt{x^{7}})dx \). Evaluate the integral by following steps: - step0: Evaluate using partial integration formula: \(\int \left(8-7x^{4}+\frac{3}{x^{16}}+18\sqrt{x^{7}}\right) dx\) - step1: Simplify the root: \(\int \left(8-7x^{4}+\frac{3}{x^{16}}+18x^{3}\sqrt{x}\right) dx\) - step2: Use properties of integrals: \(\int 8 dx+\int -7x^{4} dx+\int \frac{3}{x^{16}} dx+\int 18x^{3}\sqrt{x} dx\) - step3: Evaluate the integral: \(8x+\int -7x^{4} dx+\int \frac{3}{x^{16}} dx+\int 18x^{3}\sqrt{x} dx\) - step4: Evaluate the integral: \(8x-\frac{7x^{5}}{5}+\int \frac{3}{x^{16}} dx+\int 18x^{3}\sqrt{x} dx\) - step5: Evaluate the integral: \(8x-\frac{7x^{5}}{5}-\frac{1}{5x^{15}}+\int 18x^{3}\sqrt{x} dx\) - step6: Evaluate the integral: \(8x-\frac{7x^{5}}{5}-\frac{1}{5x^{15}}+12x^{\frac{9}{2}}-8x^{\frac{9}{2}}\) - step7: Calculate: \(8x-\frac{7x^{5}}{5}-\frac{1}{5x^{15}}+4x^{\frac{9}{2}}\) - step8: Simplify: \(8x-\frac{7x^{5}}{5}-\frac{1}{5x^{15}}+4x^{4}\sqrt{x}\) - step9: Add the constant of integral C: \(8x-\frac{7x^{5}}{5}-\frac{1}{5x^{15}}+4x^{4}\sqrt{x} + C, C \in \mathbb{R}\) The integral of the given function is \(8x - \frac{7x^{5}}{5} - \frac{1}{5x^{15}} + 4x^{4}\sqrt{x} + C\), where \(C\) is an arbitrary constant.

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The Deep Dive

To find the exact decimal of the integral \( \int\left(8-7 x^{4}+\frac{3}{x^{16}}+18 \sqrt{x^{7}}\right) d x \), we’ll first integrate each term separately. 1. The integral of \( 8 \) is \( 8x \). 2. The integral of \( -7x^4 \) is \( -\frac{7}{5} x^5 \). 3. The integral of \( \frac{3}{x^{16}} \) can be rewritten as \( 3x^{-16} \) leading to \( -\frac{3}{15} x^{-15} = -\frac{1}{5} x^{-15} \). 4. The integral of \( 18\sqrt{x^7} \) is \( 18x^{\frac{7}{2}} \times \frac{2}{9} = 4 x^{\frac{9}{2}} \). Putting it all together, we have: \[ \int\left(8-7x^{4}+\frac{3}{x^{16}}+18\sqrt{x^{7}}\right) d x = 8x - \frac{7}{5} x^5 - \frac{1}{5} x^{-15} + 4 x^{\frac{9}{2}} + C \] To express this in exact decimal form, you can evaluate at specific \( x \) values or calculate constants if needed, but the expression results in a polynomial and a rational function representing the exact integral. And there you have it—the integral in all its glory! Don't forget to add the constant of integration \( C \) to account for those sneaky constant terms. Keep practicing those integrals; they might just pop up in unexpected places!

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